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2x^2-1-(x^2-x+3)-(x^2+x-4) 用分离系数法写过程
人气:179 ℃ 时间:2020-08-14 05:01:00
解答
2x^2-1-(x^2-x+3)-(x^2+x-4)
=2x^2-1-x^2+x-3-x^2-x+4
=(2-1-1)x^2+(1-1)x+(-1-3+4)
=0+0+0
=0
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