已知(x+y)²=1 (x-y)²=1 49,x²+y²=[(x+y)²+(x-y)²]÷2=(1+149)÷2=75;与xy的值=[(x+y)²-(x-y)²]÷4=(1-149)÷4=-37;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么...