计算定积分：∫1→2[x+(1/x)]^2dx_数学解答

计算定积分：∫1→2[x+(1/x)]^2dx

人气：214 ℃　时间：2020-03-22 02:40:49

解答

∫[1,2][x+(1/x)]^2dx
=∫[1,2](x^2+1/x^2+2)dx
=(x^3/3-1/x+2x)[1,2]
=7/3+1/2+2
=29/6