[(x+1)(x-2)][(x+3)(x-4)]=24[(x²-x)-2][(x²-x)-12]=24令a=x²-x(a-2)(a-12)=24a²-14a+24=0a²-14a=0a(a-14)=0a=0,a=14x²-x=0x(x-1)=0x=0,x=1x²-x=14x²-x-14=0x=(1±√57)/2x...