原式=(1-√3i)/(√3+i)^2
=(1-√3i)/(2+2√3i)
=(1-√3i)^2/[2*(1-3)]
=(-2-2√3i)/(-4)
=(1+√3i)/2.
若前面没有括号,
原式=1-√3i/(√3+i)^2
=（7+√3i）/4.