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(1)x^2-根号2x-1/4=0 (2) X(X-4)=2-8X (3) X^2+2根号5x+10=0
用公式法解下列方程
人气:119 ℃ 时间:2020-05-14 12:57:57
解答
1.x^2-√2 x +1/2 -1/2-1/4=0(x-(√2)/2)^2 -3/4=0(x-(√2)/2)^2=3/4x-(√2)/2=±(√3)/2x1=(√3+√2)/2x2=(-√3+√2)/22.x^2-4x=2-8xx^2+4x+4=2+4(x+2)^2=6x+2=±√6x1=√6-2x2=-√6-23.x^2+2√5x+10=0x^2+2√5...
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