计算两直线(x+3)/4=(y-6)/(-3)=(z-3)/2；(x-4)/8=(y+1)/(-3)=(z+7)/3的距离直线L₁：(x+3)/4=(y-6)/(-3)=(z-3)/2；直线L₂：(x-4)/8=(y+1)/(-3)=(z+7)/3；L₁过点(-3,6,3)；方向数为A={4,-3,2}；L...