(1)f(x)=x²-2x+2=x²-2x+1+1=(x-1)²+1当X=1 时,f(x)最小值为 1(2)f(x) = -x² + 4x + 2 = -x² + 4x - 4 + 6= -(x - 2)² + 6所以当 x= 2 时,f(x)有最大值为 6