> 数学 >
已知x^2-4x+y^2+6y+13=0求x^2-2xy+y^2x^2-y^2
x^2-4x+y^2+6y+13=0
求x^2-2xy+y^2÷x^2-y^2 少个符号不好意思
人气:245 ℃ 时间:2020-06-18 19:18:08
解答
x^2-4x+y^2+6y+13=0
x^2-4x+4+y^2+6y+9=0
(x-2)^2+(y+3)^2=0
x-2=0 x=2
y+3=0 y=-3
(x^2-2xy+y^2)÷(x^2-y^2)
=(x-y)^2/[(x+y)(x-y)]
=(x-y)/(x+y)
=(2+3)/(2-3)
=-5
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版