f(x)=sin(x-π/6)由-π/2+2kπ≤x-π/6≤π/2+2kπ-π/3+2kπ≤x≤2π/3+2kπ所以原函数的单调增区间为：A=【-π/3+2kπ,2π/3+2kπ】 D=【0,π】当,k≤-1时,A∩D=空集当k=0时,A∩D=【0,2π/3】当k≥1时,A∩D=空集所...