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-8x^y*(a-b)*1/2xy^2*(1/2b-1/2a)^2=?
人气:261 ℃ 时间:2020-09-30 21:32:20
解答
-8x^y*(a-b)*1/2xy^2*(1/2b-1/2a)^2
=(-8x²y*1/2xy²)*[(a-b)*1/4(a-b)²]
=-4x³y³*1/4(a-b)³
=-x³y³(a-b)³
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