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(3y^2)^3-5y^2[2y^4-y(3y-1/5)]
计算化简
人气:158 ℃ 时间:2020-10-02 01:45:30
解答
(3y^2)^3-5y^2[2y^4-y(3y-1/5)]
=(3y^2)^3-5y^2[2y^4-3y²+1/5)]
=27y^6-10y^6+15y^4-y²
=17y^6+15y^4-y²
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