1+1/(x-2)+1+1/(x-4)=1+1/(x-3)+1+1/(x-5)
1/(x-2)+1/(x-4)=1/(x-3)+1/(x-5)
1/(x-2)-1/(x-5)=1/(x-3)-1/(x-4)
(2x-7)/(x-2)(x-5)=(2x-7)/(x-3)(x-4)
∴2x-7=0
x=7/2