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x+y-2=0,求(x²-y²)²-8(x²+y²)的值.
人气:369 ℃ 时间:2020-10-02 01:05:58
解答
x+y-2=0x+y=2(x²-y²)²-8(x²+y²)=(x+y)²﹙x-y)²-8x²-8y²=4(x²-2xy+y²)-8x²-8y²=4x²-8xy-4y²-8x²-8y²=-4(x²+2xy+y&#...=(x+y)²﹙x-y)²-8x²-8y²=4(x²-2xy+y²)-8x²-8y²请问这两步是怎么做的(x+y)²﹙x-y)²-8x²-8y² x+y=2代入(x-y)²=x²-2xy+y²=4(x²-2xy+y²)-8x²-8y²=4(x²-2xy+y²)-8x²-8y²=4x²-8xy-4y²-8x²-8y²好像哪写错了4(x²-2xy+y²)-8x²-8y²=4x²-8xy+4y²-8x²-8y²
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