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数学
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数学不等式均值定理
设x>-1,求y=(x+5)(x+2)/(x+1)函数的最值
人气:171 ℃ 时间:2020-05-23 21:37:23
解答
y=(x+1)+4/(x+1)+5>=4+5=9
y有最小值9,此时x=1,没有最大值
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