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14.2g(NH42C2O4•xH2O中含有1.204×1023个NH4+,该物质的摩尔质量是______,x的值是______.
人气:205 ℃ 时间:2020-06-02 09:55:46
解答
14.2g(NH42C2O4•xH2O中含有1.204×1023个NH4+
NH4+的物质的量=
1.204×1023
6.02×1023mol−1
=0.2mol,
则(NH42C2O4•xH2O的物质的量=
0.2mol
2
=0.1mol,
故(NH42C2O4•xH2O的摩尔质量=
14.2g
0.1mol
=142g/mol,
所以18x+18×2+24+64=142,解得x=1,
故答案为:142g/mol;1.
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