(x-1)(x-3)(x-4)(x-12)+5x^2=0解方程
人气:433 ℃ 时间:2020-03-24 16:21:11
解答
(x-1)(x-3)(x-4)(x-12)+5x^2=0(x-1)(x-12)(x-3)(x-4)+5x^2=0(x^2-13x+12)(x^2-7x+12)+5x^2=0[(x^2-10x+12)-3x][(x^2-10x+12)+3x]+5x^2=0(x^2-10x+12)^2-9x^2+5x^2=0(x^2-10x+12)^2-4x^2=0[(x^2-10x+12)-2x][(x^2-10x...
推荐
猜你喜欢