4(x+1)²=√3(x+1)
4(x+1)²-√3(x+1)=0
(x+1)(4x+4-√3)=0
(x+1)=0或(4x+4-√3)=0
x1=-1 x2=-(4-√3)/4
(x-2)²-6(x-2)+9=0
(x-2-3)²=0
x1=x2=5