> 数学 >
用分解因式法解方程:(x-2)²-5(x-2)+4=0 (x-1)(x+3)=12
用分解因式法解方程:(x-2)²-5(x-2)+4=0
(x-1)(x+3)=12
人气:330 ℃ 时间:2020-10-01 17:43:24
解答
(x-2)²-5(x-2)+4=0
(x-2-1)(x-2-4)=0
x=3 x=6
(x-1)(x+3)=12
(x-1)(x-1+4)=12
(x-1)^2+4(x-1)-12=0
(x-1+6)(x-1-2)=0
x=-5 x=3
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版