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x²-y²=1 (x-y)²-2(x-y)-3=0
人气:129 ℃ 时间:2020-06-17 04:17:17
解答
由整体思想十字相乘得:
[(x-y)+1][(x-y)-3]=0
(x-y+1)(x-y-3)=0
x-y+1=0或x-y-3=0
x=y-1或x=y+3
列方程组:
{x=y-1 或{x=y+3
x²-y²=1 x²-y²=1
{y=0 或{y=-4/3
x=-1 x=5/3
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