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5a³-3b²-5a³+4b²+2ab,其中a=-1,b=1/2
人气:188 ℃ 时间:2020-02-05 23:48:08
解答
答:
5a³-3b²-5a³+4b²+2ab,其中a=-1,b=1/2
=(5a³-5a³)+(-3b²+4b²)+2ab
=0+b²+2ab
=(b+2a)b
=(1/2 -2)*(1/2)
=(-3/2)*(1/2)
=-3/4先合并同类项,再求值对啊
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