答：
lim(x→0) [sin(1/x)+cos(1/x) ]^x
=lim(x→0) { [ sin(1/x)+cos(1/x) ] ^2 }^(x/2)
=lim(x→0) [ 1+sin(2/x) ]^(x/2) 因为：0=lim(x→0) [ 1+sin(2/x) ]^(x/2) 用洛必达法则怎么解？不符合这个法则