已知x2-x-1=0,则x4+2x+1/x5的值为?
人气:368 ℃ 时间:2020-06-10 01:49:35
解答
x^2-x-1=0(x-1/2)^2-5/4=0x-1/2=1/2*根号5 或x-1/2=-1/2*根号5x=1/2+1/2*根号5 或x=1/2-1/2*根号5将x的值代入:x^4+2x+1/x5=(x+1)^2+2x+1/[x*(x+1)^2]=x^2+2x+1+2x+1/(x^3+2x^2+x)=x+1+4x+1+1/[x*(x+1)+2(x+1)+x]=5x...
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