关于x的一元二次方程 ax平方+(a-1)x+a-1大于0 解集为一切实数 求a的取值范围
人气:220 ℃ 时间:2019-12-12 06:26:45
解答
a>0
德塔=(a-1)^2-4a(a-1)=a^2-2a+1-4a^2+4a
=-3a^2+2a+10
(a-1)(3a+1)>0
a1
综上a>1
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