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[(8-2x)*0.4+(x+3)*0.36+x*0.35]/11=0.385 (求具体计算过程)
人气:381 ℃ 时间:2020-05-16 05:06:07
解答
[(8-2x)*0.4+(x+3)*0.36+x*0.35]/11=0.385
(3.2-0.8x+0.36x+1.08+0.35x)/11=0.385
3.2-0.8x+0.36x+1.08+0.35x=4.235
-0.09x=-0.045
x=0.5
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