.52张梭哈一对的概率为什么这样计算?
The number of such hands is (13-choose-1)*(4-choose-2)*(12-choose-3)*[(4-choose-1)]^3.If all hands are equally likely,the probability of a single pair is obtained by dividing by (52-choose-5).This probability is 0.422569.
即
13c1 * 4c2 * 12c3 * 4e3 / 52c5 = 0.422569
c:组合
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