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数学
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已知实数a、b满足a²+b²=1,ab>0,求a×根号下1-b² +b×根号下1-a²的值
初一数学
快一些
人气:393 ℃ 时间:2019-08-27 11:13:45
解答
a²+b²=1 则a²=1-b²b²= 1-a²
a×根号下1-b² +b×根号下1-a²
=a*a+b*b
=a²+b²
=1
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