设动点(x,y,z),根据题意
√[(x-2)^2+(y-3)^2+(z-1)^2]=√[(x-4)^2+(y-5)^2+(z-6)^2]
两边同时平方得
(x-2)^2+(y-3)^2+(z-1)^2=(x-4)^2+(y-5)^2+(z-6)^2
化简得
4x+4y+10z-63=0