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帮我解个一元4次方程
m4+8m2+16m=0
人气:459 ℃ 时间:2020-06-04 07:35:30
解答
用matlab给的解析解~
x1 = 0
x2 = -2/3*(27+3*105^(1/2))^(1/3)+4/(27+3*105^(1/2))^(1/3)
x3 = 1/3*(27+3*105^(1/2))^(1/3)-2/(27+3*105^(1/2))^(1/3) + i*3^(1/2)*(-1/3*(27+3*105^(1/2))^(1/3)-2/(27+3*105^(1/2))^(1/3))
x4 = 1/3*(27+3*105^(1/2))^(1/3)-2/(27+3*105^(1/2))^(1/3) - i*3^(1/2)*(-1/3*(27+3*105^(1/2))^(1/3)-2/(27+3*105^(1/2))^(1/3))
转化成数值解为:
x1=0
x2=-1.5418
x3=0.7709 - 3.1278i
x4=0.7709 + 3.1278i
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