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(x+2y-3z)² 1999² 2005²-2004*2006 (4-3a)(-3a-4) (a-1)(a+1)(a²+1)
重发
(1)(x+2y-3z)²
(2) 1999²
(3)2005²-2004*2006
(4)(4-3a)(-3a-4)
(5)(a-1)(a+1)(a²+1)
人气:485 ℃ 时间:2020-06-13 11:56:06
解答
(1)(x+2y-3z)²=x^2+4y^2+9z^2+4xy-12yz-6xz(2) 1999²=(2000-1)^2=2000^2+1-4000=4000000+1-4000=3996001(3)2005²-2004*2006=2005^2-(2005^2-1)=1(4)(4-3a)(-3a-4)=(-3a)^2-4^2=9a^2-16...
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