解方程组3(x+y)-4(x-y)=4,x+y除以2+x-y除以6=1
人气:386 ℃ 时间:2020-10-01 22:31:04
解答
x+y除以2+x-y除以6=1?3(x+y)-4(x-y)=4,(x+y)/2+(x-y)/6=1写对就采纳。要完整3(x+y)-4(x-y)=4得 -X+7y=4(1)(x+y)/2+(x-y)/6=1(2)(2)去分母:3(X+Y)+(X-Y)=6 得4x+2y=6得2x+y=3(3) (1)*2 :-2x+14y=8 (4)(4)+(3):y=11/15 将y代入x=17/15对不起,题目写错了.应该是3(x+y)-4(x-y)=-9,(x+y)/2+(x-y)/6=13(x+y)-4(x-y)=9得 -X+7y=9(1)(x+y)/2+(x-y)/6=1(2)(2)去分母:3(X+Y)+(X-Y)=6 得4x+2y=6得2x+y=3(3) (1)*2 :-2x+14y=18(4)(4)+(3):y=7/5将y代入x=4/5
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