lim(x→0)[√(1+x³)-1]/[1-cos√(x-sinx)]=lim(x→0)(x³/2)/[(x-sinx)/2]=lim(x→0) x³/(x-sinx)=lim(x→0) 2x²/(1-cosx)=lim(x→0) 2x²/(x²/2)=4希望对你有帮助,望采纳,谢谢~...