| v | 2A1 |
解得:
vA1=
| 2gH |
(2)A鱼入水后,受重力、浮力和阻力,根据动能定理,有:
mghA-fAhA-F浮hA=0-
| 1 |
| 2 |
| v | 2A1 |
其中:F浮=
| 10 |
| 9 |
解得:
fA=(
| H |
| hA |
| 1 |
| 9 |
(3)同理
fB=(
| H |
| hB |
| 1 |
| 9 |
解得
| fA |
| fB |
| (9H−hA)hB |
| (9H−hB)hA |
答:(1)“A鱼”入水瞬间的速度为
| 2gH |
(2)“A鱼”在水中运动时所受阻力为(
| H |
| hA |
| 1 |
| 9 |
(3)“A鱼”和“B鱼”在水中运动时所受阻力之比
| (9H−hA)hB |
| (9H−hB)hA |

