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lim(x趋向0) x^2 / (sin^2) * x/3
人气:107 ℃ 时间:2020-06-16 02:19:02
解答
x→0lim x^2 / sin^2(x/3)=lim 9*x^2/9 / sin^2(x/3)=9*lim (x/3)^2 / sin^2(x/3)=9*lim [(x/3) / sin(x/3)]^2=9*[lim (x/3) / sin(x/3)]^2根据重要的极限:lim sinx/x=1=9*1^2=9有不懂欢迎追问
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