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数学
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简便运算(1+0.12+0.23)X(0.12+0.23+0.34) - (1+0.12+0.34)X(0.12+0.23)
人气:340 ℃ 时间:2020-05-23 13:37:05
解答
(1+0.12+0.23)X(0.12+0.23+0.34) - (1+0.12+0.23+0.34)X(0.12+0.23)
=(0.12+0.23+0.34)+(0.12+0.23)×(0.12+0.23+0.34) - (0.12+0.23)-(0.12+0.23+0.34)×(0.12+0.23)
=(0.12+0.23+0.34) - (0.12+0.23)
=0.34请问是不是简便啊? 我怎么看都不像啊呵呵
推荐
(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)=_.
(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)=_.
计算.要简便 (1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)
简便运算;0.12+0.23+0.34+……+0.89=
(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)=_.
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