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根号(10t)的导数是多少?还有f(x)=xsinx+cosx,则f`(π/2)的值为?
人气:398 ℃ 时间:2020-04-22 23:04:19
解答
(√10 t )' = ((10 t )^(1/2))' = (1/2) ((10 t )^(-1/2)) (10 t )' = 5 (10 t )^(-1/2) 先求f'(x) = sinx + x cosx - sinx = x cosx 再求 f'(π/2) = x cosx = π/2 (0) = 0
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