利用函数图像求方程-x^2+6x-9=0的实数根
人气：436 ℃ 时间：2020-05-07 16:11:11
解答
-x²+6x-9=0
-(x²-6x+9)=0
-(x-3)²=0
x=3
函数图象为开口向下,与x轴交点为(3,0)
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