若x+y分之xy=2,则-x+3xy-y分之3x-xy+3y=多少?_数学解答

若x+y分之xy=2,则-x+3xy-y分之3x-xy+3y=多少?

人气：327 ℃　时间：2019-11-02 15:43:36

解答

即x+y=xy/2
原式=[3(x-y)-xy]/[3xy-(x+y)]
=[3(xy/2)-xy]/[3xy-(xy/2)]
=(xy/2)/(5xy/2)
=1/5