求证（tanαtan2α/tan2α-tanα）+√3[(sinα)^2-(cosα)^2]=2sin(2α-π/3)_数学解答

求证（tanαtan2α/tan2α-tanα）+√3[(sinα)^2-(cosα)^2]=2sin(2α-π/3)

人气：451 ℃　时间：2019-12-01 10:38:23

解答

[tanαtan2α/(tan2α-tanα）]+√3[(sinα)^2-(cosα)^2]=sinasin2a/cosacos2a)/(sin2a/cos2a-sina/cosa)-√3cos2a=sinasin2a/cosacos2a)/[(sin2acosa-cos2asina)/cos2acosa]-√3cos2a=sinasin2a/sina-√3cos2a=2x(...