已知不等式X²-（A-1)X+(A-1）＞0的解为全体实数,求实数A的取值范围.
人气：440 ℃ 时间：2019-10-10 01:07:27
解答
答：
x^2-(a-1)x+(a-1)>0的解为全体实数,
则表示x^2-(a-1)x+(a-1)=0无实数解
判别式=(a-1)^2-4(a-1)
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