Cos80°Sin40°+Sin50°Cos10°
=sin10°cos50°+Sin50°Cos10°
=sin(10°+50°)
=sin60°
=√3/2
3题
[2sin50°+cos10°(1+√3tan10°)]/(2cos5°)
=(2sin50°+cos10°+√3sin10°)/(2cos5°)
=(2sin50°+2sin40°)/(2cos5°)
=(sin50°+sin40°)/(cos5°)
=2(sin45°cos5°)/(cos5°)
=√2