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x+3y+9y^2/(x-3y)+6x^2y/(9y^2-x^2)
人气:283 ℃ 时间:2020-04-27 16:06:05
解答
x+3y+9y^2/(x-3y)+6x^2y/(9y^2-x^2)=[(x+3y)(x-3y)+9y²]/(x-3y) + 6x²y/(9y²-x²)=x²/(x-3y) + 6x²y/(9y²-x²)=-x²/(3y-x) + 6x²y/[(3y+x)(3y-x)]=[-x²(3y+x...
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