试求关于X的函数Y=lgX/3*lgX/12的最小值
人气:172 ℃ 时间:2020-02-02 15:12:37
解答
y=lg(x/3)×lg(x/12)=(lgx-lg3)(lgx-lg12)=(lgx)^2-(lg3+lg12)lgx+lg3lg12=(lgx)^2-2lg6lgx+lg3lg12=(lgx-lg6)^2+lg3lg12-(lg6)^2=(lgx-lg6)^2-(lg2)^2故当x=6时有最小值-(lg2)^2.
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