> 数学 >
7ab-3a^2b^2+7+8ab^2+3a^2b^2-3-7ab计算
人气:182 ℃ 时间:2020-04-15 20:39:19
解答
7ab-3a^2b^2+7+8ab^2+3a^2b^2-3-7ab
=(7ab-7ab)+(3a^2b^2-3a^2b^2)+8ab^2+(7-3)
=8ab^2+4-1/2a^2ab+1/2cba^2-1/2a^2ab+1/2cba^2=-1/2a^3b+1/2cba^2=1/2a^2b(c-a)
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版