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y=sin(-2x+π/6)的单调递减区间是?求具体过程和分析
人气:190 ℃ 时间:2020-09-25 06:46:55
解答
y=sin(-2x+π/6)= -sin(2x-π/6)
2x-π/6∈(2kπ-π/2,2kπ+π/2)时单调减
所以单调减区间:(kπ-π/6,kπ+π/3),其中k∈ZA:[-π/6+2kπ,π/3+2kπ]B:[π/6+2kπ,5π/6+2kπ]C:[-π/6+kπ,π/3+kπ]D:π/6+kπ,5π/6+kπ
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