[(x-3)/2x-(x+3)/x]÷[(9-x²)/x]
=[(x-3)-2(x+3)]/(2x)×[x/(3-x)(3+x)]
=[(-x-9)/(2x)]×[x/(3-x)(3+x)]
=(x+9)/[2(x-3)(x+3)]
当x=1时,原式=10/(-16)=-5/8