计算(-4)^2÷(-8)-(-1)^10 -5^3×(-5分之2)^2÷(-0.4)^3
直接写出 5^= ,3^5= ,(-4)^3= ,-4^3= ,(-5)^4= ,-5^4= ,
(-3分之2)^3= ,-3分之2^3= .
人气:361 ℃ 时间:2020-01-28 16:48:40
解答
(-4)^2÷(-8)-(-1)^10 =-16÷8-1=-2-1=-3 -5^3×(-5分之2)^2÷(-0.4)^3=-125×(5分之2)^2÷【-(5分之2)^3】=125÷5分之2=125×2分之5=2分之6255^2= 25 ,3^5=243 ,(-4)^3=-64 ,-4^3=-64 ,(-5)^4=625 ,-...5^3=5^3=1253个5连乘,即5×5×5计算、观察、归纳与应用(1)计算;2^1=2, 2^2=4, 2^3=8,2^4=16,2^5=_______,2^6=________,2ˆ7=________, 2ˆ8=_________。(2)观察与归纳:2^n(n为正整数)的末位数字有何规律?(3)你能说出2^2012的未位数字吗?计算、观察、归纳与应用(1)计算;2^1=2, 2^2=4, 2^3=8,2^4=16,2^5=__32_____,2^6=____64____,2ˆ7=____128____, 2ˆ8=___256______。(2)观察与归纳:2^n(n为正整数)的末位数字有何规律?2,4,8,6.。。。(3)你能说出2^2012的未位数字吗?末位是6.采纳吧,早点睡。我睡了。
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