Find three consecutive integers such that twice the least integer is 12 more than the greatest.
找到3个连续的整数,例如最小整数的两倍比最大的大12.
回答：设三个数为 a,a+1,a+2
则 2a - 12 = a + 2
a = 14
即,这三个数是 14,15,16
谢谢o(∩_∩)o