12÷（1-
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=12÷
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=12×2×
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=84（只），
第一天吃：
84×
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第二天吃：
（84-12）×
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因此前两天猴子所吃桃子的总数是：
12×2=24（只）；
答：第一天和第二天猴子共吃了24只桃子．
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