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数学
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(0.25)^(-0.5)+(1/27)^(-1/3)-625^0.25
人气:417 ℃ 时间:2020-03-31 21:06:55
解答
(0.25)^(-0.5)+(1/27)^(-1/3)-625^0.25
=(0.5^2)^(-0.5)+[(1/3)^3]^(-1/3)-5^4^0.25
=0.5^[2*(-0.5)]+(1/3)^[3*(-1/3)]-5^(4*0.25)
=0.5^(-1)+(1/3)^(-1)-5
=2+3-5
=0
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